7x^2-17x+10=0

Solution for 7x^2-17x+10=0 equation:

7x^2-17x+10=0

a = 7; b = -17; c = +10;
Δ = b2-4ac
Δ = -172-4·7·10
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-3}{2*7}=\frac{14}{14}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+3}{2*7}=\frac{20}{14}
=1+3/7
$